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  1. #include <stdio.h>
  2.  
  3. // 除算の商 = 何回減算できたか
  4. int div(int m, int n)
  5. {
  6. 	if (m<n)
  7. 		return 0;
  8. 	else
  9. 		return 1 + div(m-n,n);	//減算回数のカウントアップ
  10. }
  11.  
  12. int main(void) {
  13. 	int m,n;
  14.  
  15. 	scanf("%d,%d", &m, &n);
  16. 	printf("%d",div(m,n));
  17.  
  18. 	return 0;
  19. }
  20.  
Success #stdin #stdout 0.01s 5288KB
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https://ideone.com/zvndYV
[再帰]割り算
language:
C99 (gcc 8.3)
created:
1 day ago
visibility:
public

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