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  1. #include <stdio.h>
  2.  
  3. int main() {
  4.     int a0, a1, an1, n;
  5.  
  6.     for (a0 = 1, a1 = 2, n = 0; a1 <= 1000; ) {
  7.  
  8.         an1 = 3 * a1 + 2 * a0;
  9.  
  10.         if (an1 >= 100 && an1 <= 1000) {
  11.             n++;
  12.         }
  13.  
  14.         a0 = a1;
  15.         a1 = an1;
  16.  
  17.         if (an1 > 1000) {
  18.             break;
  19.         }
  20.     }
  21.  
  22.     printf("100以上1000以下となる項の個数：%d個\n", n);
  23.  
  24.     return 0;
  25. }
Success #stdin #stdout 0s 5316KB
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Standard input is empty
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100以上1000以下となる項の個数：2個
https://ideone.com/qvlRGx
language:
C (gcc 8.3)
created:
10 hours ago
visibility:
public

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