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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. #define int long long int
  4. #define double long double
  5. #define print(a) for(auto x : a) cout << x << " "; cout << endl
  6.  
  7.  
  8. const int M = 1000000007;
  9. const int N = 3e5+9;
  10. const int INF = 2e9+1;
  11. const int LINF = 2000000000000000001;
  12.  
  13. inline int power(int a, int b, int mod=M) {
  14. int x = 1;
  15. a %= mod;
  16. while (b) {
  17. if (b & 1) x = (x * a) % mod;
  18. a = (a * a) % mod;
  19. b >>= 1;
  20. }
  21. return x;
  22. }
  23.  
  24.  
  25. //_ ***************************** START Below *******************************
  26.  
  27.  
  28.  
  29.  
  30. vector<int> a;
  31.  
  32. int consistency1(int n, int p, int q, int r){
  33.  
  34. vector<vector<vector<vector<int>>>> dp(
  35. n + 1, vector<vector<vector<int>>>(
  36. p + 1, vector<vector<int>>(
  37. q + 1, vector<int>(r + 1, INF)
  38. )
  39. )
  40. );
  41.  
  42. dp[0][0][0][0] = 0;
  43.  
  44. for(int i=1; i<=n; i++){
  45. for(int j=0; j<=p; j++){
  46. for(int k=0; k<=q; k++){
  47. for(int l=0; l<=r; l++){
  48. if(dp[i-1][j][k][l] != INF)
  49. dp[i][j][k][l] = dp[i-1][j][k][l];
  50.  
  51. if(j-1>=0){
  52. if(dp[i-1][j-1][k][1] != INF)
  53. dp[i][j][k][l] = min(dp[i][j][k][l], dp[i-1][j-1][k][l] + a[i-1]);
  54. }
  55. if(i-2>=0 && k-1>=0){
  56. if(dp[i-2][j][k-1][1] != INF)
  57. dp[i][j][k][l] = min(dp[i][j][k][l], dp[i-2][j][k-1][l] + a[i-1] + a[i-2]);
  58. }
  59. if(i-3>=0 && l-1>=0){
  60. if(dp[i-3][j][k][1-1] != INF)
  61. dp[i][j][k][l] = min(dp[i][j][k][l], dp[i-3][j][k][l-1] + a[i-1] + a[i-2] + a[i-3]);
  62. }
  63. }
  64. }
  65. }
  66. }
  67.  
  68. int sum = 0;
  69. for(int i=0; i<n; i++) sum += a[i];
  70.  
  71. return sum - dp[n][p][q][r];
  72. }
  73.  
  74.  
  75.  
  76.  
  77. int consistency2(int n, int p, int q, int r){
  78.  
  79. vector<vector<vector<vector<int>>>> dp(
  80. n + 1, vector<vector<vector<int>>>(
  81. p + 1, vector<vector<int>>(
  82. q + 1, vector<int>(r + 1, -INF)
  83. )
  84. )
  85. );
  86.  
  87. dp[0][0][0][0] = 0;
  88.  
  89. for(int i=1; i<=n; i++){
  90. for(int j=0; j<=p; j++){
  91. for(int k=0; k<=q; k++){
  92. for(int l=0; l<=r; l++){
  93.  
  94. if(dp[i-1][j][k][l] != -INF)
  95. dp[i][j][k][l] = dp[i-1][j][k][l] + a[i-1];
  96.  
  97. if(j-1>=0){
  98. if(dp[i-1][j-1][k][l] != -INF)
  99. dp[i][j][k][l] = max(dp[i][j][k][l], dp[i-1][j-1][k][l]);
  100. }
  101. if(i-2>=0 && k-1>=0){
  102. if(dp[i-2][j][k-1][l] != -INF)
  103. dp[i][j][k][l] = max(dp[i][j][k][l], dp[i-2][j][k-1][l]);
  104. }
  105. if(i-3>=0 && l-1>=0){
  106. if(dp[i-3][j][k][l-1] != -INF)
  107. dp[i][j][k][l] = max(dp[i][j][k][l], dp[i-3][j][k][l-1]);
  108. }
  109. }
  110. }
  111. }
  112. }
  113.  
  114. return dp[n][p][q][r];
  115. }
  116.  
  117.  
  118.  
  119.  
  120.  
  121.  
  122.  
  123.  
  124.  
  125.  
  126.  
  127.  
  128. int practice(int n, int p, int q, int r){
  129.  
  130.  
  131. return 0;
  132. }
  133.  
  134.  
  135.  
  136.  
  137.  
  138. void solve() {
  139.  
  140. int n, p, q, r;
  141. cin>> n >> p >> q >> r;
  142.  
  143. a.resize(n);
  144. for(int i=0; i<n; i++) cin >> a[i];
  145.  
  146. cout << consistency1(n, p, q, r) << " " << consistency2(n, p, q, r) << endl;
  147.  
  148.  
  149. }
  150.  
  151.  
  152.  
  153.  
  154.  
  155. int32_t main() {
  156. ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
  157.  
  158. int t = 1;
  159. // cin >> t;
  160. while (t--) {
  161. solve();
  162. }
  163.  
  164. return 0;
  165. }
Success #stdin #stdout 0s 5320KB
stdin
9 1 1 1
3 1 0 5 1 6 5 -1 -100 
stdout
16 16