#include <iostream>
using namespace std;
/*
Declarăm si citim “n”.
Declarăm matricea și vectorul în care vom stoca ultima coloana a matricei.
Cu o structura repetitiva, parcurg “n” pasi:
		Cu o alta structura repetitiva, citim elementele matricei:
Cu ajutorul unei structuri decizionale, vom verifica dacă indicele coloanei este egal cu “n”:
In caz afirmativ, folosindu-ne de indicele liniilor, 
stocăm în vector, elementul curent.
 
     6. Cu un “for” care ruleaza de la “n + 1” pana la n / 2 + 1 inclusiv:
Cu o structura repetitiva care ruleaza de la “1” pana la “n” inclusiv:
Dacă indicele liniei este mai mare decat “n / 2 + 1”: 
	mutam elementele liniei anterioare pe linia curentă.
Altfel copiem în linia curentă elementele vectorului, folosindu-ne de indicele coloanei curente.
     7. Incrementam pe “n”.
*/
 
const int MAX_SIZE = 10;
 
int main() {
	int n;
	cin >> n;
	int mt[MAX_SIZE + 2][MAX_SIZE + 1], v[MAX_SIZE + 1];
	for (int i = 1; i <= n; ++i) {
		for (int j = 1; j <= n; ++j) {
			cin >> mt[i][j];
			if (j == n) {
				v[i] = mt[i][j];
			}
		}
	}
	for (int i = n + 1; i >= n / 2 + 1; --i) {
		for (int j = 1; j <= n; ++j) {
			if (i > n / 2 + 1) {
				mt[i][j] = mt[i - 1][j];
			} else {
				mt[i][j] = v[j];
			}
		}
	}
	++n;
	for (int i = 1; i <= n; ++i) {
		for (int j = 1; j < n; ++j) {
			cout << mt[i][j] << " ";
		}
		cout << "\n";
	}
	return 0;
}
 
 

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10
15 15  4 54  8 48 48 47 87 48
54 64 84 68 78 78 79 87  9 79 
86  5 46 54 68 87 89  7  8 79
8  79  8 54 47 79 11 19 20 100
15 15  4 54  8 48 48 47 87 48
54 64 84 68 78 78 79 87  9 79 
86  5 46 54 68 87 89  7  8 79
8  79  8 54 47 79 11 19 20 100
54 64 84 68 78 78 79 87  9 79 
86  5 46 54 68 87 89  7  8 79