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  1. #include<stdio.h>
  2. int main(){
  3.    int n,factor_count=0;
  4.    printf("enter n;");
  5.    scanf("%d",&n);
  6.    printf("factors:");
  7.    for (int i=1;i<=n;i++){
  8.     if(n%i==0){
  9.         printf("%d ",i);
  10.         factor_count++;
  11.     }
  12.    } printf("\nfactors:%d",factor_count);
  13. }
  14.  
Success #stdin #stdout 0.01s 5316KB
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stdin
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Standard input is empty
stdout
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enter n;factors:1 2 29 58 379 758 10991 21982 
factors:8
https://ideone.com/Pv1BqO
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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