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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int i,j=0;
  5. 	for(i=0;s[i+1]!='\0';i++);
  6. 		for(j=0;j<=(i/2);j++){
  7. 		if(s[j]!=s[i-j]) return 0;
  8. 			 {
  9. return 1;
  10. }
  11. }
  12. 	//回文になっているとき１を返す
  13. 	//回文になっていないとき０を返す
  14. }
  15.  
  16. //メイン関数は書き換えなくてよいです
  17. int main(){
  18.     char s[100];
  19.     scanf("%s",s);
  20.     printf("%s -> %d\n",s,isPalindrome(s));
  21.     return 0;
  22. }
  23.  
Success #stdin #stdout 0.01s 5288KB
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girafarig
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girafarig -> 1
https://ideone.com/KUwP4z
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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