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  1. #include <stdio.h>
  2. void calculate(int (*a)[4]) {
  3.     int sum[3];
  4.     for (int i = 0; i < 3; i++) {
  5.         sum[i] = 0;
  6.         for (int j = 0; j < 4; j++) {
  7.             sum[i] += a[i][j];
  8.         }
  9.     }
  10.     for (int i = 0; i < 3; i++) {
  11.         printf("sum[%d] = %d\n", i, sum[i]);
  12.     }
  13. }
  14. int main() {
  15.     int a[3][4] = {
  16.         {1, 2, 3, 4},
  17.         {5, 6, 7, 8},
  18.         {9, 10, 11, 12}
  19.     };
  20.     calculate(a);
  21.     return 0;
  22. }
Success #stdin #stdout 0.01s 5328KB
comments (?)
stdin 
Standard input is empty
stdout 
sum[0] = 10
sum[1] = 26
sum[2] = 42
https://ideone.com/HFQ4kh
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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