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  1. #include <stdio.h>
  2.  
  3. // xのn乗を返す再帰関数
  4. int power(int x, int n) {
  5.     if (n == 0)
  6.         return 1;
  7.     else
  8.         return x * power(x, n - 1);
  9. }
  10.  
  11. int main(void) {
  12.     int x, n;
  13.  
  14.     printf("xとnを入力（例: 2 3）: ");
  15.     scanf("%d %d", &x, &n);
  16.  
  17.     printf("%d^%d = %d\n", x, n, power(x, n));
  18.  
  19.     return 0;
  20. }
  21.  
Success #stdin #stdout 0.01s 5288KB
comments (?)
stdin
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2 10
stdout
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xとnを入力（例: 2 3）: 2^10 = 1024
https://ideone.com/1CGXOt
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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